RIGID FRAME ANALYSIS By Gary Argraves - C Version 2025 ======================================================= Project Designation ? Frame, 1 story by 3 bays Date: 2025-06-27 09:23:20 ___INPUT FRAME SIZE___ How many Stories ? 1 How many Portals ? 3 ___INPUT FRAME GEOMETRY (units=feet)___ Input story heights. Story # 1 ? 12.00 Total height= 12.00 Input beam lengths. Beam # 1 ? 24.00 Beam # 2 ? 30.00 Beam # 3 ? 24.00 Total length= 78.00 Page width (pixels) = 1800 ? Page height (pixels) = 1100 ? Plot Scale Length (ft/in) = 15 ? Plot Scale Moment (kip-ft/inch) = 150 ? ___INPUT MEMBER SIZES - Moment of Inertia (I) (units=inch^4)___ STORY # 1 ------- Beam # 1 ? 290.00 Beam # 2 ? 941.00 Beam # 3 ? 290.00 Column # 1 ? 146.00 Column # 2 ? 227.00 Column # 3 ? 227.00 Column # 4 ? 146.00 ___BASE JOINT TYPE___ 1. Fixed 2. Pinned Enter 1 or 2 ? 1 ___________ MACRO LOAD DEFINITION ____________ +-A--+---C---+ W ! #########--W \ ====================== -- Story 2 -+-#I I I I | #I I I I C--| #I I I I | #====================== -- Story 1 -+-#I I I I A--| I P1 I P2 I P3 I __|__I______I______I______I___ Ground S=0 :Lateral Load S=-1 :Next Macro Definition S>0 :Gravity Load S=-2 :Quit Macro Definition Macro # 1 Load #1 ------- ------ Enter Story # S=? 0 Intensity W=? 40.00 Location A=? 11.90 Length C=? 0.10 Macro # 1 Load #2 ------- ------ Enter Story # S=? -1 Macro # 2 Load #2 ------- ------ Enter Story # S=? 1 Intensity W=? 1.50 Location A=? 0.00 Length C=? 24.00 Macro # 2 Load #3 ------- ------ Enter Story # S=? 1 Intensity W=? 2.40 Location A=? 24.00 Length C=? 30.00 Macro # 2 Load #4 ------- ------ Enter Story # S=? 1 Intensity W=? 1.50 Location A=? 54.00 Length C=? 24.00 Macro # 2 Load #5 ------- ------ Enter Story # S=? -2 ___APPLY LOADS TO FRAME___ # > 0 :Macro Loading # < 0 :Single Load # = 0 :Quit loading Enter Loading Designation ? WIND LOADING Enter # ? 1 Enter # ? 0 INFO: Setting up structural matrix... INFO: Matrix assembly completed INFO: Solving matrix system using Gaussian elimination... INFO: Matrix solution completed successfully === ANALYSIS RESULTS === Beam Moment-L Moment-R Shears-L Shears-R (#) (Kip-ft) (Kip-ft) (Kips) (Kips) ---- -------- -------- ------ ------ Story 1 1 -3.236 -2.562 -0.242 0.242 2 -4.885 -4.868 -0.325 0.325 3 -2.600 -3.331 -0.247 0.247 Column Moment Shears Axial (#) (Kip-ft) (Kips) (Kips) ---- -------- ------ ------ Story 1 1 3.236 -3.318 -0.242 4.747 -0.682 2 7.448 1.323 -0.084 8.433 -1.323 3 7.468 1.326 0.078 8.443 -1.326 4 3.331 0.669 0.247 4.694 -0.669 Joint Rotation Displacement (#) (Radians) (Feet) ---- --------- ------ Story 1 1 -0.000258827 0.00477982 2 -0.000125036 3 -0.000123727 4 -0.000268940 Story 0 5 0.000000000 6 0.000000000 7 0.000000000 8 0.000000000 ============================================ 1. Define More Macros. 2. Reload the Frame. 3. Exit Program. Enter Option ? 2 ___APPLY LOADS TO FRAME___ # > 0 :Macro Loading # < 0 :Single Load # = 0 :Quit loading Enter Loading Designation ? ALL LOADS Enter # ? 1 Enter # ? 2 Enter # ? 0 INFO: Setting up structural matrix... INFO: Matrix assembly completed INFO: Solving matrix system using Gaussian elimination... INFO: Matrix solution completed successfully === ANALYSIS RESULTS === Beam Moment-L Moment-R Shears-L Shears-R (#) (Kip-ft) (Kip-ft) (Kips) (Kips) ---- -------- -------- ------ ------ Story 1 1 26.845 -113.588 14.386 21.614 2 143.850 -153.604 35.675 36.325 3 108.426 -33.412 21.126 14.874 Column Moment Shears Axial (#) (Kip-ft) (Kips) (Kips) ---- -------- ------ ------ Story 1 1 -26.845 -7.078 14.386 -10.294 3.078 2 -30.263 -3.390 57.289 -10.422 3.390 3 45.178 6.040 57.451 27.298 -6.040 4 33.412 4.429 14.874 19.735 -4.429 Joint Rotation Displacement (#) (Radians) (Feet) ---- --------- ------ Story 1 1 -0.003225723 0.00477982 2 -0.002517218 3 0.002268454 4 0.002697956 Story 0 5 0.000000000 6 0.000000000 7 0.000000000 8 0.000000000 ============================================ 1. Define More Macros. 2. Reload the Frame. 3. Exit Program. Enter Option ? 3 ***** E N D O F R U N *****